Lvalues and RValues
lvalues and rvalues
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An object is a contiguous region of storage. An lvalue is an expression that refers to such an object. The original
definition of lvalue referred to an object that can appear on the left-hand side of an assignment. However, const
objects are lvalues that cannot be used in the left-hand side of an assignment. Similarly, an expression that can appear
in the right-hand side of an expression (but not in the left-hand side of an expression) is an rvalue. For example
#include
using namespace std;
int& f();
void func()
{
int n;
char buf[3];
n = 5; // n is an lvalue; 5 is an rvalue
buf[0] = 'a'; // buf[0] is an lvalue, 'a' is an rvalue
string s1 = "a", s2 = "b", s3 = "c"; // "a", "b", "c" are rvalues
s1 = // lvalue
s2 +s3; //s2 and s3 are lvalues that are implicitly converted to rvalues
s1 = //lvalue
string("z"); //temporaries are rvalues
int * p = new int; //p is an lvalue; 'new int' is an rvalue
f() = 0; //a function call that returns a reference is an lvalue
s1.size(); //otherwise, a function call is an rvalue expression
}
An lvalue can appear in a context that requires an rvalue; in this case, the lvalue is implicitly converted to an rvalue.
An rvalue cannot be converted to an lvalue. Therefore, it is possible to use every lvalue expression in the example as an rvalue, but not vice versa.
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An object is a contiguous region of storage. An lvalue is an expression that refers to such an object. The original
definition of lvalue referred to an object that can appear on the left-hand side of an assignment. However, const
objects are lvalues that cannot be used in the left-hand side of an assignment. Similarly, an expression that can appear
in the right-hand side of an expression (but not in the left-hand side of an expression) is an rvalue. For example
#include
using namespace std;
int& f();
void func()
{
int n;
char buf[3];
n = 5; // n is an lvalue; 5 is an rvalue
buf[0] = 'a'; // buf[0] is an lvalue, 'a' is an rvalue
string s1 = "a", s2 = "b", s3 = "c"; // "a", "b", "c" are rvalues
s1 = // lvalue
s2 +s3; //s2 and s3 are lvalues that are implicitly converted to rvalues
s1 = //lvalue
string("z"); //temporaries are rvalues
int * p = new int; //p is an lvalue; 'new int' is an rvalue
f() = 0; //a function call that returns a reference is an lvalue
s1.size(); //otherwise, a function call is an rvalue expression
}
An lvalue can appear in a context that requires an rvalue; in this case, the lvalue is implicitly converted to an rvalue.
An rvalue cannot be converted to an lvalue. Therefore, it is possible to use every lvalue expression in the example as an rvalue, but not vice versa.
Labels: Cpp
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